php+ajax+json 详解及实例代码

php+ajax+json 实例代码

html页面:


    <html>
    <head>
    <meta http-equiv="content-type" content="text/html;charset=utf-8" />
    <script type="text/javascript" src="jquery-1.8.2.min.js"></script>
    <script type="text/javascript">
     $(function(){
       $("#send").click(function(){
        var cont = $("input").serialize();
        $.ajax({
          url:'ab.php',
          type:'post',
          dataType:'json',
          data:cont,
          success:function(data){
           var str = data.username + data.age + data.job;
           $("#result").html(str);
        }
      });
     }); 
     });
    </script>
    </head>
    <body>
    <div id="result">一会看显示结果</div>
    <form id="my" action="" method="post">
          <p><span>姓名:</span> <input type="text" name="username" /></p>
         <p><span>年龄:</span><input type="text" name="age" /></p>
         <p><span>工作:</span><input type="text" name="job" /></p>
    </form>
    <button id="send">提交</button>
    </body>
    </html>

php页面:


    <?php
    header("Content-type:text/html;charset=utf-8");
        $username = $_POST['username'];
        $age = $_POST['age'];
        $job = $_POST['job'];
        $json_arr = array("username"=>$username,"age"=>$age,"job"=>$job);
        $json_obj = json_encode($json_arr);
        echo $json_obj;
    ?>

使用post方式


    <script type="text/javascript">
     $(function(){
     $("#send").click(function(){
       var cont = {username:$("input")[0].value,age:$("input")[1].value,job:$("input")[2].value};
       var url = 'ab.php';
       $.post(url,cont,function(data){
        var res = eval("(" + data + ")");//转为Object对象
       var str = res.username + res.age + res.job;
      $("#result").html(str);
      });
     }); 
     });
    </script>

感谢阅读,希望能帮助到大家,谢谢大家对本站的支持!


所属标签

无标签